4[6-(1+2x)+10]=2(10-3x)

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Solution for 4[6-(1+2x)+10]=2(10-3x) equation:


Simplifying
4[6 + -1(1 + 2x) + 10] = 2(10 + -3x)
4[6 + (1 * -1 + 2x * -1) + 10] = 2(10 + -3x)
4[6 + (-1 + -2x) + 10] = 2(10 + -3x)

Reorder the terms:
4[6 + -1 + 10 + -2x] = 2(10 + -3x)

Combine like terms: 6 + -1 = 5
4[5 + 10 + -2x] = 2(10 + -3x)

Combine like terms: 5 + 10 = 15
4[15 + -2x] = 2(10 + -3x)
[15 * 4 + -2x * 4] = 2(10 + -3x)
[60 + -8x] = 2(10 + -3x)
60 + -8x = (10 * 2 + -3x * 2)
60 + -8x = (20 + -6x)

Solving
60 + -8x = 20 + -6x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '6x' to each side of the equation.
60 + -8x + 6x = 20 + -6x + 6x

Combine like terms: -8x + 6x = -2x
60 + -2x = 20 + -6x + 6x

Combine like terms: -6x + 6x = 0
60 + -2x = 20 + 0
60 + -2x = 20

Add '-60' to each side of the equation.
60 + -60 + -2x = 20 + -60

Combine like terms: 60 + -60 = 0
0 + -2x = 20 + -60
-2x = 20 + -60

Combine like terms: 20 + -60 = -40
-2x = -40

Divide each side by '-2'.
x = 20

Simplifying
x = 20

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